
| Surviving College Algebra |
| "When all you want is the grade" |

| Linear Functions |
In
solving equations there are many steps to go through and rules to follow. Generally in solving equations, get the term
with the variable by itself and then solve for the variable. Ask the question
“Is the variable by itself?”. If the answer is no, “What is with it and
what is it doing with it?”. After asking, and answering these questions,
“undo” or solve the equation. Use the following rules.
More advanced
rules will follow later.
Remember- What is done to
one side of the equation (everything on either the left or right of the equal
sign), MUST be done to the other!
x +
5 = 7
Subtract
5 from both sides
x = 2
“Is
x by itself?”
Yes,
so the answer is x = 2.
Example
x –
5 = 10
Add
five to both sides.
x =
15
x
is by itself so the answer is x = 15.
Example
4x
= 12
To
undo the multiplication with 4, divide by 4.
=
On
the left side, 4 divided by 4 is 1, and 1 times anything (here it is x) is
itself (x), so the 4’s cancel out on the left side.
=3.
x =
3
Answer!
Example
=
12
To
undo the division of 6, multiply by 6.
(6)
= 12 (6)
The
6’s on the left side cancel out and 12 (6) is 72.
x =
72
Answer!
Now
do some multi-step problems. Always get the term with the variable, x in this
case, by itself first.
Example
-3x
– 4 = 5
Undo
the –4 first. So add 4 to both sides. This will get the x term by itself.
-3x
= 9
Undo
the multiplication by dividing by -3.
=
The
-3’s on the left cancel and
= -3.
x =
-3
Answer!
Example
+
7 = 11
Subtract
7 from both sides.
= 4
Multiply
both sides by 3, since x is being divided by 3.
(3)
= 4(3)
The
3’s on the left cancel and 4(3) = 12.
x =
12
Answer!
Sometimes
things have to be a done a little different.
With any problem involving fractions or division, look at all the
denominators (numbers on bottom) and multiply by the least common
denominator. This will get rid of all
division or fractions in the problem.
Example
= 2
Since
there is one fraction, the LCD will be its denominator, which is 5. Multiply every
term on both sides by 5.
(5)
= 2(5)
The
5’s on the left cancel and 2(5) = 10
y +
2 = 10
Subtract
2 from both sides.
y = 8
Answer!
Example
3(a
– 2) = -21
Get
rid of all parentheses by first distributing the 3.
3a
– 6 = -21
Add
6 to both sides.
3a = -15
Divide
both sides by 3.
a =
-5
Answer!
Here
are some further examples of problems using combinations of the previous
topics.
Example
= - 15
Multiply
both sides by –2, this will get the k term by itself as well as get rid of all
fractions.
(-
2)
= - 15(-2)
The
–2’s on the left side cancel and –15(-2)= 30.
3k
= 30
Divide
both sides by 3 to get k by itself.
=
The
3’s on the left cancel and
= 10.
k =
10
Answer!
Example
3(2x
–5) = -27
Distribute
the 3 to get rid of the parentheses.
6x
– 15 = -27
Add
15 to both sides.
6x
= -12
Divide
both sides by 6.
x =
- 2
Answer!
Example
=
-1
Multiply
both sides by 3, to get rid of all the parentheses.
(3)
= -1(3)
The
3’s cancel out, and –1(3)= -3.
-4x
+ 5 = -3
Now,
subtract 5 from both sides.
-4
x = -8
Divide
both sides by –4.
x =
2
Answer!
The
reason all of the previous problems fell under the category of “linear” is because the highest exponent with
the variable in each case is 1.