
| Surviving College Algebra |
| "When all you want is the grade" |

| Graphing |
In
this section linear equations will be discussed in more detail and how to graph
them. The first thing to realize about
linear expressions is that they are of degree 1. This means the largest exponent is 1. Here are some examples of linear equations.
x =
4
y =
2
a =
4 + c
x =
y + 1
y =
2 x –1
x +
y = 4
3 x
+ 4 y = 9
4 a
– 6 b = 5
Here
are some examples of some that are not,
y =
x 2 + 2
y =
-3 x 2
y =
x 4 + 3 x 3 – 6 x 2 - 3 x + 2
All to look for is the degree (highest
exponent). In the first two (y = x 2
+ 2 and y = -3x 2) the degree is 2. But in the last example y = x 4
+ 3 x 3 - 6x 2 - 3 x + 2 ,
the degree is 4. This is all to be
concerned with for now. If it is not of
degree 1, it is not linear. In other
words, if its degree is anything higher than 1 it falls into a different class
that will be covered later.
Anything of degree 1 is called “linear”. This also means that the graph will be a
line.
In
order to be able to graph, one must be able to plot coordinates. In order to do that, know what the x and
y-axis are. The x-axis is the main line
that runs back and forth on any graph.
The y-axis runs up and down.
Where these two lines cross is called the origin.
y-axis
x-axis
Any point on a graph is labeled with two numbers. The first number is called the x-coordinate and the second is the y-coordinate. The x-coordinates start at the left as being negative and as they move to the right they become positive once they cross the y-axis. The y-axis is negative on bottom and positive on top. The origin has a coordinate of (0,0), remember that the first 0 is the x-coordinate and the second is the y-coordinate. Now here is a graph with some points to show some examples of graphing points.
![[image]](Graphing1_files/image002.gif)
(-2,6)
(2,3)
(0,0)
![]()
(5,-1)
(-3,-5)
In
graphing equations or functions, look at what kind it is to start with. As explained earlier, determine if it is
linear or not. If it is linear (or of
degree 1) it is a line. Hence, they are “linear”. Now to graph it, get the equation in the
correct form. The form that is recommend is the slope-intercept form. That means that y is by itself on one side of
the equation. When they take on the form
y = m x + b, where m is called the slope and b is called the y-intercept. Now slope is nothing more than how much the
graph changes. The easiest way to think
about slope is in the form of business graphs.
Think about the following graphs like they would be seen in a business
meeting.
A

![]()
B

C
![]()
D

If
these were business graphs and someone asked, “Here are four different companies (A,
B, C, and D) which one would you like to invest your money into?” The obvious answer would be “A”. Now that is the easiest way to understand
graphs and slope. Slope is how much
something is changing. The steeper the line is on the graph the more slope it would have. Following is a summary of the graphs
and their slopes.
Company
A one would
assume is doing very well. Moving from
left to right it keep getting higher and higher. On a graph, its slope is positive.
Graph
B is a
company that is not doing so well, therefore it has negative slope. That is, when moving from left to right it
keeps getting lower and lower.
Graph
C is a
company that is not changing at all.
That means that the slope would be 0.
Company D is really confusing. It says that it is going straight up. Now with common sense everyone knows that it is not possible for a company graph to go straight up. Therefore, the slope of that graph would be undefined, or more exactly, ¥(infinity).
Since slope is m in y = m x + b, look at the other
part of the y = m x + b equation, the b.
It is called slope-intercept form, so the other part would be the
intercept. Intercept is a lot like the
word intersection. In this case look at
the y-intercept. That means, where the
graph crosses the y-axis. The letter in
the equation for this is the b. In the
following graphs there is a line along with the point where it crosses the
y-axis or y-intercept.
(0,2)
This graph has a y-intercept of 2, because it
crosses the y-axis at the point (0, 2).
Looking at the graph, notice that the slope is positive (Remember the
business graphs?).
![[image]](Graphing1_files/image013.gif)
(0,-4)
Looking at this graph it crosses the y-axis at –4,
thus making its’ y-intercept, or b, equal to –4. The slope in this graph is negative because
from left to right it looks like it is going down.
One important thing to notice is that so far in the
two graphs there have been 2 different y-intercepts, (0,2) and (0, -4). In these two points, along with every other y-intercepts, the x-value (first number in (x, y)) will always
be 0.
Slope is represented by a number and not just being
positive or negative. Slope can also be
called the rate of change. The term
“rate of change” is referring to slope.
Slope is best defined by the following equation. 
When people refer to this formula it is usually read
as “slope is equal to rise over run.”
Rise simply means how much something is rising. Keep in mind that “rise” is referring to how
much the elevation is changing, or the height.
The word “run” would refer to the change back and forth. There is an
illustration of that in a moment. First focus on how much something is
rising. To do that, find two points that
the line goes through.
![[image]](Graphing1_files/image016.gif)
(4,7)
(0,1)
Look at the two points, any
two points along the line would work.
The only condition was that the line had to go through those
points. In the next
graph look at the “rise”. That is
how far it is changing height from one point to the other.
![]()
Count on the graph and see that the difference in
the height, or y direction, between the two points, as shown in the graph, is
6. This is the rise. Next, look at the difference in the back and
forth, or x, direction.
![]()
Notice that the distance covered back and forth is
4. This is the run. Applying the formula
gets
This should be the last
step. Keep in mind that the slope can be
simplified, therefore
.
One more thing to consider
is whether the slope of this graph is positive or negative. By thinking back to the business graphs and
looking at this graph one can see that the slope is positive.
To write the equation of a
line in slope-intercept form (y = m x + b) first find the slope, which is m,
and in this case it is equal to 3/2.
Then find the y-intercept, or b, in this case by looking at the graph
and seeing where it crosses the y-axis, the y-intercept is 1. Substitute the m and b into the general
equation results in,
.
This is the equation of
the line in slope-intercept form.
Note- When
writing the equation of a line, do not fill in numbers for x and y, only the m
and b (slope and y-intercept). This is
done because the x’s and y’s are always changing.
When looking at a line, notice that x can equal 0, 1,2,
or any other number, and the y value will change depending upon what the x
value is. That is why the x and y are called variables. The slope of a straight line as well as where
it crosses the y-axis will never change, and are therefore called constants.
Find the equation of the
following line in slope intercept form.
The first things to find are the slope and
y-intercept. The y-intercept is
relatively simple to find. By just looking
at the graph, notice that it crosses the y-axis at –3. That makes b = - 3. In order to find the slope, find the rise and
the run between any two points that the graph goes through.
Note- When choosing the two points to find the slope,
chose two points where the line goes exactly through the intersection on the
grid. In other words, make sure the line
goes through that exact point.
![[image]](Graphing1_files/image027.gif)
The two points used to determine the rise and run
were (0,-3) and (4, -4). The rise is
equal 1 and the run is equal to 4 between these two points. Therefore,
.
Notice
that the slope in this case is negative (from the business graphs).
That
would get a slope of
.
Remember
that slope is m in the slope intercept form, and as discussed earlier the
y-intercept, or b, is –3.
By
plugging into the formula for m and b results in
.
Here
are some examples where information is given and one is asked to graph the
line.
Example
Graph the following line.

First,
see what the y intercept is. It is 6,
since that is the b value, which means the line crosses the y-axis at 6. So point (0,6) is on
the graph. Graph that point.
![[image]](Graphing1_files/image036.gif)
With that point graphed, use the slope of 2/5 from
that point. Start at that point (0, 6), rise
2 and run 5 to get to the next point (5,8).
![[image]](Graphing1_files/image037.gif)
![]()
Now there is an additional point that is on the line
(5,8). With any
two points one can graph a line. All to
do from here is to draw a line that goes through those two points.
![[image]](Graphing1_files/image040.gif)
Answer!
This is the graph of
.
Note- When
doing the rise over run in the previous example, the run was to the right. Do this anytime that there is a positive
slope. If one has a negative slope then
run to the left after rising.
Example
Graph
.
The –3 represents slope so
the slope is -3. Now –3 is the same
thing as
. Since slope is
usually thought of as rise over run, it helps to have it in the form of one
number over another. Thinking about it like
, means that rise is 3 and run is 1. The negative is used when graphing, do not
assign it to the 3 on top but rather to the entire fraction. Slope is known and the y-intercept is
–2. As discussed earlier if –2 is the
y-intercept then point (0-2) is on the graph so put that point on the graph.
![[image]](Graphing1_files/image046.gif)
From that point rise 3 and run 1. Keep in mind the slope is negative, so run to
the left.
![[image]](Graphing1_files/image047.gif)
Here are two points, (0,-2) and (-1,1). All to do now is
to draw a straight line between them, and the graph is complete.
![[image]](Graphing1_files/image048.gif)
Answer! The graph of y = -3x-2.
Example
Graph the line that has a slope of
and goes
through the point (-4, 2).
The first things to do is
to graph the point, rise 1, and run 2 from it.
![[image]](Graphing1_files/image051.gif)
Starting at the point (-4,2)
rising 1 and running 2 will be at the point (-2,3). Now that there are two points, draw a line
between them.
![[image]](Graphing1_files/image052.gif)
Answer!
Example
Graph the line that goes through the two points (2, 1) and (3, -5).
The first thing to do is to graph the two points. Once these two points are graphed, draw a line between them.
![[image]](Graphing1_files/image053.gif)
Answer!
There are 2 other situations that need to be addressed here. They are graphs of lines like the ones before but 2 special cases of lines.
Example
Graph y = 3
This same equation can be written in the form y = 0x + 3 and mean the same thing. The best way to understand this problem is to think “Where on the graph is y = 3?” The points (-2,3), (0,3), and (7,3). All have y values of three. Notice in the equation that there is not an x, that means that it does not matter what x is. So basically y = 3, and x is anything. The graph of y = 3 is actually a horizontal or flat line going back and forth. This is the only way to have y = 3 everywhere along the line. If one were to plot the points discussed earlier and graph a line through them, would result in the following graph.
![[image]](Graphing1_files/image054.gif)
Answer!
Example
Graph x = -9 Look for
when is x = -9. The answer will be a
vertical line where y can be anything but the x has to be -9. Here is a graph of x = -9.
Answer!
The above definitions of slope and slope-intercept form are useful when graphing. It is also very useful in working these types of problems algebraically (without a graph).
Example
Find the equation, in slope-intercept form, of the line that goes through point (1,2) and has a slope of 3.
The first thing to realize is that the slope is 3. That means that in the slope-intercept form of a line, m = 3. Write that down.
y = 3 x + b
Find out the b (y-intercept) in this equation. To do this, use the point (1,2) that the line goes through. Let x = 1 and y = 2 just like it does in the point. Plug those values in for x and y in the equation.
2 = 3(1) + b
Now there is an equation to solve for b. Solve for b, by first multiplying the 3 and 1.
2 = 3 + b
Subtract 3 from both sides.
-1 = b b = -1.
Go back to the very first equation, y = 3x + b. Remember all that was needed to be in slope-intercept form was the value of b. Since b = -1, plug it in for b.
y = 3 x - 1
Answer!
Example
Find the equation, in slope-intercept form, of the line that goes through point (3,-2) and has a slope of -1.
Plug the value for slope (-1) into the slope-intercept formula.
y = -1x + b
Before trying to find b, simplify this formula by dropping the 1 in front of the x. It is understood there is a 1 there when being multiplied.
y = -x + b
Plug the 3 and –2 in for the x and y. Make sure not to get these two in the wrong order!
-2 = -(3) + b
Solve for b by first multiplying the 3 and the -.
-2 = -3 + b
Add 3 to both sides.
1 = b
Plug the b into the formula.
y = -x + 1
Answer!
Example
Find the equation, in slope-intercept form, of the line
that goes through point (-2, -6) and has a slope of ![]()
Plug in the slope.
y =
x + b
Plug in the –2 and –6 for x and y.
-6 =
(-2) + b
Solve for b by first multiplying.
-6 =
+ b
Subtract
from both
sides.
= b
Plug this value for b in to the equation.
y =
x -
Answer!
Earlier this formula for slope was used.

When talking
about the rise, it is actually referring to how far it travels up and down, or
in the y-direction. To find out how much
something changes, subtract. Subtracting the amount one started with, from the
amount ended up with, typically does this.
This is done with two points to calculate slope. In other words, subtract the y values for
rise and subtract the x values for run.
Here is another formula for calculating the slope.

This is using sub
notation (the little numbers by the y’s and x’s). The sub notation does not mean to multiply or
anything like that, but is simply used to name the different variables. Knowing that, understand this formula as
saying “The second y minus the first y over the second x minus the first
x.” It does not matter which point is
number 1 in sub notation or number 2. Be
consistent in the fact that the second y must be with the second x and so
on. Anytime subtracting, one is actually
measuring a difference. This is denoted
in math with the D(delta) symbol. Using this symbol, rewrite the formula.

This new formula
is very useful because it allows the calculation of the slope without having to
graph it and calculate the rise over the run.
Here are a few examples applying it.
Example
Find the slope of
the line that goes through the two points (1, 2) and (5, 7).
The first thing
to do to keep organized is to name the two points. It does not matter how they are named. But once done, keep it
throughout the entire problem. Go
ahead and name (1, 2) as point 1, and (5, 7) as point 2.
Point 1 = (1,2)
Point 2 = (5,7)
The points are
named so find out the variables used to calculate the slope. The variables are x1
,y1 ,x2 , and y2 . x1 is
simply the x in the first point and so on.
x1 = 1
y1 = 2
x2 = 5
y2 = 7
Plug these values
in for the variables in the slope equation.
Make sure to keep the y’s
on top.
Solve.
Answer!
Example
Find the slope of the line that goes
through the two points (3,4) and (6,1).
Name the points and find the variables.
x1= 3
y1= 4
x2= 6
y2= 1
Plug into the formula.
Solve.
This will simplify.
-1
Answer!
Example
Find the slope of
the line that goes through the two points (-1, 0) and (3, 8).
Name the points
and find the variables.
x1 = -1
y1 = 0
x2 = 3
y2 = 8
Plug into the
formula.
Solve.
Simplify.
Simplify.
2
Answer!
Example
Find the equation
of the line that goes through the two points (2,-3) and (0,7).
In order to find
the equation, one must know the slope and the y-intercept. Find the slope first by using the same method
as before. Name the points and find the variables.
x1 = 2
y1 =
-3
x2 = 0
y2 = 7
Plug into the
formula.
Solve.
Simplify.
-5
This is the slope
so plug it into the formula.
y = -5 x + b
To complete the
equation, find b. Do this just like
earlier, by plugging in one of the point values for x and y. It does not matter which point to plug in
either point 1 or point 2. Decide which
one will be easiest to work with and use it.
The second point (0,7) will be easiest in this
case so plug it in.
7 = -5(0) + b
Solve for b by
first multiplying.
7 = 0 + b
Simplify.
7 = b
Now the slope is
known as well as the y-intercept so plug both of them in.
y = -5x + 7
Answer!
Generally, the
most useful form for a line is slope intercept form. Which is what has been used
so far. Standard form is another
form that many like to use. It is not as
easy to use in graphing purposes but algebraically it can be easier in some
circumstances.
Standard form of
a line is
Ax + By = C.
Where A, B, and C
are constants (numbers). For example in
the equation 3x – 4y = 2, A = 3, B = - 4 and C = 2. Make sure when writing a line in standard
form that A is a positive whole number.
Work out the problems just like before and if standard form is asked
for, convert it to standard form from slope intercept form for the last step.
Example
Write y = 2x –6
in standard form.
To go to standard
form subtract 2x from both sides.
-2x + y = -6
The only thing left to do is to get the A term, -2, to be positive. To do this divide everything on both sides of the equation by a –1.
2x – y = 6
Answer!
Example
Write
in standard
form.
Instead of dealing with fractions the best thing to do is to find the least common multiple of all the denominators in the problem and multiply every term by that. In this case there is only one denominator (2) so multiply every term by 2. This will get rid of all the fractions that occur in an equation.
2y = -1x + 8
Simplify the –1 in front of the x.
2y = -x + 8
Add x to both sides.
x + 2y = 8
Answer!